Which term of the AP 3,15,27,39,...will be 120 more than its 21st term?
3,15,27,39,...(given)
We know (for an AP).....(1)
For ,
a=3
d=12
n=21
Lets assume the term l which is 120 more than
So value of l = 243+120=363
Putting the VALUE IN EQUATION (1)
363=3+(n-1)12
363=3+12n-12
363=12n-9
12n=372
n=31
The required number of the term is 31st.