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Find the equation of the line which passes through the point minus 4, 3 and the portion of the line intercepted between the axes is divided internally in the ratio 5 ratio 3 by this point?

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Let the line cut the x axis at (\mathrm{a}, 0)  and Y axis at (0, \mathrm{b}) Therefore
It is given that the point (-4,3) divides the line internally in 5: 3 ratio. Hence applying the formula for internal division of line segment, we get \frac{3 \mathrm{a}}{8}=-4 and

\frac{5 \mathrm{b}}{8}=3
Hence \mathrm{a}=\frac{-32}{3}$ \text{and} $\mathrm{b}=\frac{24}{5}
Using slope intercept form we get

\frac{x}{\frac{-32}{3}}+\frac{y}{\frac{24}{5}}=1\\ \\ 9 x-20 y+96=0

Posted by

Satyajeet Kumar

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