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  • A and B are two events such that P(A) = 0.54, P(B) = 0.69 and P(A ∩ B) = 0.35. Find (ii) P(A´ ∩ B´)

7.(ii)  A and B are two events such that \small P(A)=0.54,  \small P(B)=0.69 and  \small P({A}\cap {B})=0.35. Find (ii)  \small P({A}'\cap {B}')   

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Given, P(A) = 0.54, P(B) = 0.69, P(A \cap B) = 0.35

And, P(A \cup B) = 0.88

(ii) A' \cap B'= (A \cup B)'  [De Morgan’s law]

So, P(A' \cap B') = P(A \cup B)' = 1 - P(A \cup B) = 1 - 0.88 = 0.12

\therefore  P(A' \cap B') = 0.12

Posted by

HARSH KANKARIA

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