Q. A concave mirror produces three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Where is the image located?
Here Given Magnification:
m= -3 (real image)
The object distance :
u =-10cm
Now As we know,
Hence,
The image is at 30cm in front of the mirror.
Given :- U = -10cm as we know object is always on left , therefore -ve sign]
Therefore m -3
As , m = -v/u
Therefore -v/u = -3
-v / -10 = -4
12 x (-4) by cross multiplication
V = -30
Answer
A/Q
m= -3(real imaze)
now the object distance
u= -10cm
now we all know
m= -v/u
v=-m*u
v=-(-3)*(-10)
v= -30cm
therefore,
the imaze is 30cm in front of the mirror
Given height of image is three times object
h'=3h
h'/h=-v/u
3h/h=-v/-10
3=-v/-10
-v=3*-10
-v=-30
V=30