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  • A die is thrown, find the probability of following events: (iv) A number more than 6 will appear

3.(iv)     A die is thrown, find the probability of following events:

            (iv) A number more than \small 6  will appear
 

Answers (1)

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Sample space when a die is thrown, S = {1,2,3,4,5,6}

\therefore Number of possible outcomes n(S) = 6

Let E be the event of getting a number more than 6 will appear = \phi

\therefore n(E) = 0

\therefore P(E) = \frac{n(E)}{n(S)}  = \frac{0}{6} 

= 0

Posted by

HARSH KANKARIA

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