Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • A die is thrown, find the probability of following events: (iv) A number more than 6 will appear

3.(iv)     A die is thrown, find the probability of following events:

            (iv) A number more than \small 6  will appear
 

Answers (1)

best_answer

Sample space when a die is thrown, S = {1,2,3,4,5,6}

\therefore Number of possible outcomes n(S) = 6

Let E be the event of getting a number more than 6 will appear = \phi

\therefore n(E) = 0

\therefore P(E) = \frac{n(E)}{n(S)}  = \frac{0}{6} 

= 0

Posted by

HARSH KANKARIA

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

No changes in exam, IA system: CBSE rebuts claims of syllabus reduction, open book exams in 2025
anam-khan

Fact-check: CBSE hasn't reduced syllabus by 15%, internal assessments will not be 40% of score in 2025
anam-khan

CBSE date sheet 2025 for Classes 10, 12 likely in November last week: Reports

Latest Question