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  • A die is thrown once. Find the probability of getting a prime number

13.(i)     A die is thrown once. Find the probability of getting a prime number

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Possible outcomes when a die is thrown = {1,2,3,4,5,6}

Number of possible outcomes once = 6

(i) Let E be the event of getting a prime number.

Prime numbers on the die are = {2,3,5}

Number of favourable outcomes = 3

\therefore P(E) = \frac{favourable\ outcomes}{total\ outcomes} = \frac{3}{6}

= \frac{1}{2}

Therefore, the probability of getting a prime number is  \dpi{100} \frac{1}{2}

 

Posted by

HARSH KANKARIA

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