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  • A flashlight has 8 batteries out of which 3 are dead. If two batteries are selected without replacement and tested, the probability that both are dead is A.33/56

A flashlight has 8 batteries out of which 3 are dead. If two batteries are selected without replacement and tested, the probability that both are dead is

\\ A.\frac{33}{56} \\\\ B.\frac{9}{64} \\\\ C.\frac{1}{14} \\\\ D.\frac{3}{28}

Answers (1)

Given-

Total number of batteries: n= 8

Number of dead batteries are = 3
Therefore, Probability of dead batteries is  \frac{3}{8}
If two batteries are selected without replacement and tested

Then, Probability of second battery without replacement is  \frac{2}{7}
Required probability = \frac{3}{8}\times \frac{2}{7}= \frac{3}{28}

Posted by

infoexpert22

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