Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • A series LCR circuit with R =20 omega ,L = 1. 5 H and C = 35 omega F is connected to a variable-frequency 200 V ac supply. When the frequency of the supply equals the natural frequency of the circuit.

Q7.9  A series LCR circuit with R=20\Omega, L=1.5H  and c=35\mu F is connected to a variable-frequency 200\; V ac supply. When the frequency of the supply equals the natural frequency of the circuit, what is the average power transferred to the circuit in one complete cycle?

Answers (1)

best_answer

Given,

Resistance R=20\Omega

Inductance L=1.5H

Capacitance C=35\mu F=35*10^{-6}F

Voltage supply V = 200V

At resonance, supply frequency is equal to the natural frequency, and at the natural frequency, the total impedance of the circuit is equal to the resistance of the circuit 

as inductive and capacitive reactance cancels each other. in other words,

Z = \sqrt{\left ( \omega L-\frac{1}{\omega C} \right )^2+R^2}=\sqrt{0^2+R^2}=R=20\Omega

As 

 \omega L=\frac{1}{\omega C}

Now,

Current in the circuit

I=\frac{V}{Z}=\frac{200}{20}=10A

Average Power transferred in the circuit :

P=VI=200*10=2000W

Hence average power transferred is 2000W.

Posted by

Pankaj Sanodiya

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE board exams 2025 from February 15; Class 10, 12 subject-wise marks distribution
anam-khan

CBSE Date Sheet 2025: Class 10, 12 board exam dates soon on cbse.gov.in; previous trends, sample papers
anam-khan

CBSE Board Exams 2025: 75% attendance must for students to be eligible, reiterates board

Latest Question