Q : 8 ABCD is a rectangle in which diagonal AC bisects as well as . Show that: diagonal BD bisects as well as .
In ADB,
AD = AB (ABCD is a square)
5=7.................1(angles opposite to equal sides are equal )
5=8.................2 (alternate angles)
From 1 and 2, we have
7=8.................3
and 7 =6.................4(alternate angles)
From 1 and 4, we get
5=6.................5
Hence, from 3 and 5, diagonal BD bisects angles B as well as angle D.