Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Calculate the pH of the following solutions: (b) 0.3 g of Ca(OH)_2 dissolved in water to give 500 mL of solution.

7.49     Calculate the pH of the following solutions: 

(b)      0.3 g of Ca(OH)_2 dissolved in water to give 500 mL of solution. 

Answers (1)

best_answer

The calcium hydroxide ion dissociates into-
Ca(OH)_{2}\rightarrow Ca^{2+}+2OH^-
Molecular weight of Ca(OH)_{2} = 74 
the concentration of [Ca(OH)_{2}] = \frac{0.3\times 1000}{74\times500} = 0.0081 M

 \therefore [OH^-]= [Ca(OH)_2] = 0.0081 M

We know that,
[H^+] = \frac{K_w}{[OH^-]} = \frac{10^{-14}}{0.0162}
                                  = 61.7 \times 10^{-14}

Thus P^H = - \log [H^+]= -\log (61.7 \times 10^{-14})
                                               = 14 - 1.79  = 12.21

Posted by

manish

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE wants international boards reined in; letter to education ministry seeks directions for AIU
anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens

Latest Question