Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Calculate the 'spin only' magnetic moment of M^2+ (aq) ion (Z = 27).

8.8   Calculate the ‘spin only’ magnetic moment of  M^{2+}\; _{(aq)} ion (Z=27).

Answers (1)

best_answer

Atomic number (Z)= 27
So the electronic configuration cobalt (Co) is 3d^{7}, 4s^{2}
M^{2+}\; _{(aq)} ion means, it loses its two electrons and become d^{7} configuration. And it has 3 unpaired electrons
So, \mu = \sqrt{n(n+2)} , where n = no. of unpaired electron
by putting the value of n= 3
we get, \mu = \sqrt{15}
                 \approx 4\ BM

Posted by

manish

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Extra time in CBSE exams for students with type 1 diabetes: Kerala SHRC seeks report on plea
anam-khan

No changes in exam, IA system: CBSE rebuts claims of syllabus reduction, open book exams in 2025
anam-khan

Fact-check: CBSE hasn't reduced syllabus by 15%, internal assessments will not be 40% of score in 2025

Latest Question