2. Check whether the value given in the brackets is a solution to the given equation or not:
(a) n + 5 = 19 (n = 1)
(b) 7n + 5 = 19 (n = – 2)
(c) 7n + 5 = 19 (n = 2)
(d) 4p – 3 = 13 (p = 1)
(e) 4p – 3 = 13 (p = – 4)
(f) 4p – 3 = 13 (p = 0)
(a) Put n = 1 in the equation, we have :
n + 5 = 15
or 1 + 5 = 15
or 6 15
Thus n = 1 is not a solution.
(b) Put n = - 2, we have :
7n + 5 = 19
or 7(-2) + 5 = - 14 + 5 = - 9 19.
So, n = - 2 is not a solution to given equation.
(c) Put n = 2, we have :
7n + 5 = 19
or 7(2) + 5 = 14 + 5 = 19 = R.H.S
Thus n = 2 is the solution for the given equation.
(d) Put p = 1 , we have :
4p - 3 = 13
or 4(1) - 3 = 1 13 .
Thus p = 1 is not a solution.
(e) Put p = - 4 , we get :
4p - 3 = 13
or 4(1) - 3 = 1 13 .
Thus p = 1 is not a solution.
(f) Put p = 0 , we get :
4p - 3 = 13
or 4(0) - 3 = - 3 13 .
Thus p = 0 is not a solution.