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  • Consider the D -T reaction (deuterium tritium fusion) Calculate the energy released in MeV in this reaction from the data:

Q.13.28 (i) Consider the D–T reaction (deuterium-tritium fusion)

                  _{1}^{2}\textrm{H}+_{1}^{3}\textrm{H}\rightarrow _{2}^{4}\textrm{He}+n

                 (a) Calculate the energy released in MeV in this reaction from the data:

                  m(_{1}^{2}\textrm{H})=2.014102\; u

                   m(_{1}^{3}\textrm{H})=3.016049\; u
              

Answers (1)

best_answer

The mass defect of the reaction is 

\\\Delta m=m(_{1}^{2}\textrm{H})+m(_{1}^{3}\textrm{H})-m(_{2}^{4}\textrm{He})-m(_{0}^{1}\textrm{n})\\ \Delta m=2.014102+3.016049-4.002603-1.008665\\ \Delta m=0.018883u

1u = 931.5 MeV/c2

Q=0.018883\times931.5=17.59 MeV

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