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  • Eight coins are tossed together. The probability of getting exactly 3 heads is A.1/256

Eight coins are tossed together. The probability of getting exactly 3 heads is
A.\frac{1}{256}

B.\frac{7}{32}

C.\frac{5}{32}

D.\frac{3}{32}

Answers (1)

Given-
probability distribution \mathrm{P}(\mathrm{X}=\mathrm{r})={ }^{\mathrm{n}} \mathrm{C}_{\mathrm{r}}(\mathrm{p})^{r} \mathrm{ q}^{\mathrm{n}-\mathrm{r}}
Total number coin is tossed,  n=8 
The probability of getting head, \mathrm{p}=1 / 2
The probability of getting tail,\mathrm{q}=1 / 2
The Required probability

\\={ }^{8} \mathrm{C}_{3}\left(\frac{1}{2}\right)^{3}\left(\frac{1}{2}\right)^{8-3}\\$ $\frac{8 \times 7 \times 6}{3 \times 2} \times \frac{1}{2^{8}}=\frac{7}{32}

Posted by

infoexpert22

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