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  • Evaluate the definite integrals in Exercises 1 to 20. Integral 2 to 3 1/x dx

Evaluate the definite integrals in Exercises 1 to 20.

    Q2.    \int_2^3\frac{1}{x}dx

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Given integral: I = \int_2^3\frac{1}{x}dx

Consider the integral \int_2^3\frac{1}{x}dx

\int \frac{1}{x}dx = \log|x|

So, we have the function of x, f(x) = \log|x|

Now, by Second fundamental theorem of calculus, we have

I = f(3)-f(2)

=\log|3|-\log|2| = \log \frac{3}{2}

Posted by

Divya Prakash Singh

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