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  • Factorise : (ii) x^3 - 3x ^2 - 9x - 5

Factorise : x^3 - 3x^2 -9x -5

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Solution

Given polynomial is  x^3 - 3x^2 -9x -5
Now, by the hit and trial method we observed that  (x+1)  is one of the factors of a given polynomial.
By long division method, we will get

We know that  Dividend = (Divisor \times Quotient) + Remainder

 x^3 - 3x^2 -9x -5=(x+1)(x^2-4x-5)
 = (x+1)(x^2-5x+x-5)            
 = (x+1)(x-5)(x+1)
Therefore, on factorization of  x^3 - 3x^2 -9x -5 we will get  (x+1)(x-5)(x+1)

Posted by

Gautam harsolia

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