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Q7.11(a) Figure shows a series LCR circuit connected to a variable frequency 230\: V source. Determine the source frequency which drives the circuit in resonance. (\text{where,}\ L=5H, C=80\mu F \ \text{and} R=40\Omega)

     

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Given: Variable frequency supply voltage V=230V

Inductance L=5.0H

Capacitance C=80\mu F=80*10^{-6}F

Resistance R=40\Omega

Resonance angular frequency in this circuit is given by :

w_{resonance}=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{5*80*10^{-6}}}=\frac{1000}{20}=50rad/sec

Hence, this circuit will be in resonance when the supply frequency is 50 rad/sec.

Posted by

Pankaj Sanodiya

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