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13    Fill in the blanks in following table: 

      

  P(A) P(B) P(A\cap B) P(A\cup B)
(i) \frac{1}{3} \frac{1}{5} \frac{1}{15} ...
(ii) 0.35 ... 0.25 0.6
(iii) 0.5 0.35 ... 0.7

 

Answers (1)

best_answer

We know,

  P(A \cup B) = P(A)+ P(B) - P(A \cap B)

(i) P(A \cup B) =  \frac{1}{3}+\frac{1}{5}-\frac{1}{15} = \frac{5+3-1}{15} = \frac{7}{15}

(ii)  0.6 = 0.35 + P(B) - 0.25

\implies P(B) = 0.6 - 0.1 = 0.5

(iii)  0.7 = 0.5 + 0.35 - P(A \cap B)

\implies P(A \cap B) = 0.85 - 0.7 = 0.15

  P(A) P(B) P(A\cap B) P(A\cup B)
(i) \frac{1}{3} \frac{1}{5} \frac{1}{15}

\boldsymbol{\frac{7}{15}}
(ii) 0.35 0.5 0.25 0.6
(iii) 0.5 0.35 0.15 0.7
Posted by

HARSH KANKARIA

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