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Fill in the blanks  The third term of a G.P. is 4, the product of the first five terms is ................ 

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The third term of a G.P is given by T_{3}=4

Let the common ratio be ‘r’   

\\T_{1}=\frac{4}{r^{2}} , T_{2}=\frac{4}{r} , ~T_{4}=4r , T_{5}=4r^{2} \\\\

    Product of first 5 terms  = \left( \frac{4}{r^{2}} \right) \left( \frac{4}{r} \right) \left( 4 \right) \left( 4r \right) \left( 4r^{2} \right) =4^{5}=1024 \\\\

 

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