Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find an approximation of (0.99)^5 using the first three terms of its expansion.

Q7. Find an approximation of (0.99)5 using the first three terms of its expansion.

Answers (1)

best_answer

As we can write 0.99 as 1-0.01,

(0.99)^5=(1-0.001)^5=^5C_0(1)^5-^5C_1(1)^4(0.01)+^5C_2(1)^3(0.01)^2+\:other \:negligible \:terms

\Rightarrow (0.99)^5=1-5(0.01)+10(0.01)^2

\Rightarrow (0.99)^5=1-0.05+0.001

\Rightarrow (0.99)^5=0.951

Hence the value of   (0.99)^5  is 0.951 approximately.

Posted by

Pankaj Sanodiya

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 Supplementary Result 2026: Scanned copy, verification, re-evaluation dates announced
anam-khan

SC asks CBSE to protect students affected by OSM evaluation in admissions
anam-khan

CBSE Class 12 Compartment Result 2026 LIVE: 12th supplementary marksheet out at results.digilocker.gov.in

Latest Question