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  • Find energy of each of the photons which (ii) have wavelength of 0.50 angstrom.

2.6    Find energy of each of the photons which

  (ii) have wavelength of 0.50 Å.

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For the wavelength \lambda = 0.50\times10^{-10}m.

The energy of each of the photons will be:

E = h\vartheta = \frac{hc}{\lambda} = \frac{(6.626\times10^{-34}J.s)\times(3\times10^{15}s^{-1})}{0.50\times10^{-10}m} = 3.98\times10^{-15}J

Posted by

Divya Prakash Singh

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