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Q : 4       (i)  Find equation of line joining \small (1,2) and \small (3,6) using determinants.

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As we know the line joining \small (1,2) ,\small (3,6)  and let say a point on line A\left ( x,y \right ) will be collinear.  

Therefore area formed by them will be equal to zero.

\triangle = \frac{1}{2}\begin{vmatrix} 1 &2 &1 \\ 3& 6 &1 \\ x & y &1 \end{vmatrix} = 0

So, we have:

=1(6-y)-2(3-x)+1(3y-6x) = 0

or 6-y-6+2x+3y-6x = 0 \Rightarrow 2y-4x=0

Hence, we have the equation of line \Rightarrow y=2x.

 

Posted by

Divya Prakash Singh

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