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  • Find the 20th term of the series 2 × 4 + 4 × 6 + 6 × 8 + ... + n terms.

22.  Find the 20th term of the series 2 \times 4+4\times 6+\times 6\times 8+....+n terms.

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the series = 2 \times 4+4\times 6+\times 6\times 8+....+n

\therefore n^{th}\, term=a_n=2n(2n+2)=4n^2+4n

\therefore a_2_0=2(20)[2(20)+2]

           =40[40+2]

           =40[42]

           =1680

Thus, the 20th term of series is 1680

 

 

 

 

 

Posted by

seema garhwal

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