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Q : 2    Find the amount of water displaced by a solid spherical ball of diameter

            (ii)     \small 0.21\hspace{1mm}m

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The solid spherical ball will displace water equal to its volume. 

Given,

The radius of the sphere = r = \frac{0.21}{2}\ m

We know, Volume of a sphere = \frac{4}{3}\pi r^3

\therefore The required volume of the sphere = \frac{4}{3}\times\frac{22}{7}\times \left(\frac{0.21}{2} \right )^3

\\ = 4\times22\times \frac{0.01\times 0.21\times 0.21}{8}

\\ = 11\times 0.01\times 0.21\times 0.21

\\ =0.004851\ m^3

Therefore, amount of water displaced will be 0.004851\ m^3

Posted by

HARSH KANKARIA

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