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Q.12  Find the direction cosines of the vector \hat i + 2 \hat j + 3 \hat k

Answers (1)

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Let 

\vec a=\hat i + 2 \hat j + 3 \hat k

\left |\vec a \right |=\sqrt{1^2+2^2+3^2}=\sqrt{14}

 Hence direction cosine of \vec a are

 \left ( \frac{1}{\sqrt{14}},\frac{2}{\sqrt{14}} ,\frac{3}{\sqrt{14}}\right )

 

Posted by

Pankaj Sanodiya

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