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  • Find the general solution: dy/dx = (1 + x^2 ) (1 + y^2)

6. Find the general solution:

      \frac{dy}{dx} = (1+x^2)(1+y^2)

Answers (1)

best_answer

Given, in the question

\frac{dy}{dx} = (1+x^2)(1+y^2)

\\ \implies \int \frac{dy}{(1+y^2)} = \int (1+x^2)dx

(\int \frac{dx}{(1+x^2)} =tan^{-1}x +c)

\\ \implies tan^{-1}y = x+\frac{x^3}{3} + C

Posted by

HARSH KANKARIA

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