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10.   Find the indicated terms in each of the sequences in Exercises 7 to 10 whose nth terms are: 

a _n = \frac{n ( n-2)}{ n+3 }; a _{20}

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Given : a _n = \frac{n ( n-2)}{ n+3 }

Put n=20,

a _2_0 = \frac{20 ( 20-2)}{ 20+3 }=\frac{360}{23}

Hence, value of a _2_0=\frac{360}{23}

Posted by

seema garhwal

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