Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the projection of the vector

Q4 Find the projection of the vector \hat i + 3 \hat j + 7 \hat k  on the vector 7\hat i - \hat j + 8 \hat k

Answers (1)

best_answer

Let 

\vec a =\hat i + 3 \hat j + 7 \hat k

\vec b=7\hat i - \hat j + 8 \hat k

The projection of \vec a on  \vec b is 

\frac{\vec a.\vec b}{\left | \vec b \right |}=\frac{(\hat i+3\hat j+7\hat k)(7\hat i-\hat j+8\hat k)}{\left | 7\hat i-\hat j+8\hat k \right |}=\frac{7-3+56}{\sqrt{7^2+(-1)^2+8^2}}=\frac{60}{\sqrt{114}}

Hence, projection of vector \vec a on  \vec b is 

\frac{60}{\sqrt{114}}

 

 

Posted by

Pankaj Sanodiya

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Admit Card 2026 (OUT) LIVE: Class 10 and 12 theory exam hall ticket at parikshasangam.cbse.gov.in
anam-khan

CBSE Admit Card 2026 LIVE: How to download CBSE Class 10th, 12th hall ticket when out; exam dates, guidelines
anam-khan

CBSE 2026 Admit Card LIVE: CBSE Class 10, 12 hall ticket soon at cbse.gov.in; direct link, datesheet, updates

Latest Question