Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the values of k for which the line (k–3) x – (4 – k^2) y + k^2 –7k + 6 = 0 is (c) Passing through the origin.

Q : 1     Find the values of k for which the line                                                                                                 (k-3)x-(4-k^2)y+k^2-7k+6=0  is 

               (c) Passing through the origin.

Answers (1)

best_answer

Given equation of line is 
(k-3)x-(4-k^2)y+k^2-7k+6=0
It is given that it passes through origin (0,0)
Therefore,
(k-3).0-(4-k^2).0+k^2-7k+6=0
k^2-7k+6=0
k^2-6k-k+6=0
(k-6)(k-1)=0
k = 6 \ or \ 1
Therefore, value of k is 6 \ or \ 1

Posted by

Gautam harsolia

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 history paper 2025 moderately difficult, tested students’ understanding
anam-khan

CBSE Class 12 Computer Science Exam Analysis 2025: Paper 'moderate', but 'tougher' than last three years
anam-khan

CBSE Class 12 Accountancy Exam Analysis 2025: Paper ‘moderate', includes application-based questions

Latest Question