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Q9   Find |\vec x |  , if for a unit vector \vec a , ( \vec x -\vec a ) . ( \vec x + \vec a ) = 12

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Given in the question that

( \vec x -\vec a ) . ( \vec x + \vec a ) = 12

And we need to find \left | \vec x \right |

\left | \vec x \right |^2-\left | \vec a \right |^2 = 12

\left | \vec x \right |^2-1 = 12

\left | \vec x \right |^2 = 13

\left | \vec x \right | = \sqrt{13}

So the value of \left | \vec x \right | is \sqrt{13}

Posted by

Pankaj Sanodiya

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