Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • For what values of a and b the intercepts cut off on the coordinate axes by the line ax + by + 8 = 0 are equal in length but opposite in signs to those cut off by the line 2x – 3y + 6 = 0 on the axes.

For what values of a and b the intercepts cut off on the coordinate axes by the line ax + by + 8 = 0 are equal in length but opposite in signs to those cut off by the line 2x – 3y + 6 = 0 on the axes.

Answers (1)

Given equation is  ax+by+8=0  or  ax+by= -8 

 Now dividing by-8 to both sides \frac{a}{-8}x+\frac{b}{-8}y = 1  \frac{x}{\left (-\frac{8}{a} \right )}+\frac{y}{\left (-\frac{8}{b} \right )} = 1

 So the intercepts are -\frac{8}{a}  and  -\frac{8}{b}

 Now, the second equation which is given is 2x-3y+6=0  or  2x-3y=-6

 Dividing by-6 on both sides -\frac{2}{-6}x-\frac{3}{-6}y=1

 \frac{x}{-3}+\frac{y}{2}=1

 So, the intercepts are-3 and 2 

 Now, according to the question -\frac{8}{a}=3  and -\frac{8}{b}=-2

 a=-\frac{8}{3} and b=4

Posted by

infoexpert22

View full answer

Similar Questions

Latest Question