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  • Given the standard electrode potentials K^+/ K, Ag^+/Ag arrange these metals in their increasing order of reducing

8.29 Given the standard electrode potentials

K^{+}/K = -2.93 V   Ag^{+}/Ag = 0.80V

Hg^{2+}/Hg= 0.79V

Mg^{2+}/Mg = -2.37V  Cr^{3+}/Cr = -0.74V

arrange these metals in their increasing order of reducing power. 

 

Answers (1)

best_answer

Answer-

A negative electrode potential (E^{0})means redox couple is a stronger reducing agent. So as per data the increasing order of the following is-

Ag<Hg<Cr<Mg<K

Posted by

Gautam harsolia

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