Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

If a parallelepiped is formed by planes drawn through the points (5, 8, 10) and (3, 6, 8) parallel to the coordinate planes, then the length of diagonal of the parallelepiped is

A. $2\sqrt{3}$

B. $3\sqrt{2}$

C. $\sqrt{2}$

D. $\sqrt{3}$

Answers (1)

The answer is the option (a) $2\sqrt{3}$

Given: The parallelepiped passes through A(5,8,10) & B(3,6,8)

Thus,

Length of the diagonal, AB = $\sqrt{(5-3)^{2}+(8-6)^{2}+(10-8)^{2} }$

= $\sqrt{4+4+4}$ = $2\sqrt{3}$

Posted by

infoexpert22

View full answer

Similar Questions

Latest Question