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In a compound, nitrogen atoms (N) make cubic close packed lattice and metal atoms (M) occupy one-third of the tetrahedral voids present. Determine the formula of the compound formed by M and N?

Answers (1)

Let the no. of atoms per unit cell be n. For ccp lattice the value of n is 4
Number of tetrahedral voids generated = 2\times n =2\times 4 = 8
We know that only one-third of tetrahedral voids are occupied by metal M.

Number of metal atoms M=13 \times 8 

 M:N=83:4=2:3

 Thus formula is M_2N_3
 

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