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  • In a Young’s double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in

Q10.4   In a Young’s double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment.

Answers (1)

best_answer

Given,

Distance between screen and slit D=1.4m

Distance between slits d=0.28mm=0.28*10^{-3}m

Distance between central and fourth bright fringe u=1.2cm=1.2*10^{-2}m

Now,

as we know, the distance between two fringes in a constructive interference is given by 

u=n\lambda \frac{D}{d}

where n= order of fringe (which is 4 here) and \lambda is the wavelength of light we are using.

so from here,

\lambda = \frac{ud}{nD}=\frac{1.2*10^{-2}*0.28*10^{-3}}{4*1.4}=6*10^{-7}m

Hence wavelength os the light is 600nm

 

Posted by

Pankaj Sanodiya

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