3. In Fig. 6.30, if AB CD, EF
CD and
GED = 126°, find
AGE,
GEF and
FGE.
Given AB || CD, EFCD and
GED =
In the figure\ given,
GE is transversal. So, that AGE =
GED =
[Alternate interior angles]
Also, GEF =
GED -
FED
=
Since AB is a straight-line
Therefore, AGE +
FGE =
So, FGE =