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  • Integrate the functions x upon 9 - 4 x ^2

 Q15  Integrate the functions  \frac{x}{9- 4 x ^2 }

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Given function  \frac{x}{9- 4 x ^2 },

Assume the 9-4x^2 =t

 \therefore -8xdx =dt

\implies \int\frac{x}{9-4x^2} = -\frac{1}{8}\int \frac{1}{t}dt

= \frac{-1}{8}\log|t| +C

Now back substituting the value of t ;

= \frac{-1}{8}\log|9-4x^2| +C , where C is any constant value.

Posted by

Divya Prakash Singh

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