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  • Prove that summation Binomial Theroem Exercise 8.1 14.

Q14.    Prove that \sum_{r = 0}^n3^r \ ^nC_r = 4^n

Answers (1)

As we know from Binomial Theorem,

\sum_{r = 0}^na^r \ ^nC_r = (1+a)^n

Here putting a = 3, we get, 

\sum_{r = 0}^n3^r \ ^nC_r = (1+3)^n

\sum_{r = 0}^n3^r \ ^nC_r = 4^n

Hence Proved.

Posted by

neha

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