Get Answers to all your Questions

header-bg qa

Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power.

Ion

Reduction potential E^{\ominus }/V

ClO_{4}^{-}

E^{\ominus }=1.19V

IO_{4}^{-}

E^{\ominus }=1.65V

BrO_{4}^{-}

E^{\ominus }=1.74V

(i) ClO_{4}^{-} > IO_{4}^{-} > BrO_{4}^{-}

(ii) IO_{4}^{-} > BrO_{4}^{-}>ClO_{4}^{-}

(iii) BrO_{4}^{-} > IO_{4}^{-} >ClO_{4}^{-}

(iv) BrO_{4}^{-} > ClO_{4}^{-} >IO_{4}^{-}

Answers (1)

The answer is the option (iii).A higher reduction potential means that there is greater tendency to get reduced. Therefore, the order of oxidizing power is as follows

BrO_{4}^{-} > IO_{4}^{-} >ClO_{4}^{-}

Posted by

infoexpert23

View full answer