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  • Show that the points (2, 3, 4), (– 1, – 2, 1), (5, 8, 7) are collinear.

4. Show that the points (2, 3, 4), (– 1, – 2, 1), (5, 8, 7) are collinear.

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We have the points,  A (2, 3, 4),B (– 1, – 2, 1),C (5, 8, 7);

And as we can find the direction ratios of the line joining the points (x_{1},y_{1},z_{1}) \ and\ (x_{2},y_{2},z_{2}) is given by x_{2}-x_{1}, y_{2}-y_{1}, \ and\ z_{2}-z_{1}. 

The direction ratios of AB are (-1-2), (-2-3),\ and\ (1-4) i.e., -3,\ -5,\ and\ -3

The direction ratios of BC are (5-(-1)), (8-(-2)),\ and\ (7-1) i.e., 6,\ 10,\ and\ 6.

We can see that the direction ratios of AB and BC are proportional to each other and is -2 times.

\therefore AB is parallel to BC. and as point B is common to both AB and BC,

Hence the points A, B and C are collinear.

Posted by

Divya Prakash Singh

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