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  • Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).

Q: 11.18 Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon). 

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For a photon we know that it's momentum (p) and Energy (E) are related by following equation

E=pc

we also know

E=h\nu

Therefore the De Broglie wavelength is

\\\lambda =\frac{h}{p}\\ \lambda =\frac{h}{E/c}\\ \lambda =\frac{hc}{h\nu }\\ \lambda =\frac{c}{\nu }

The above de Broglie wavelength is equal to the wavelength of electromagnetic radiation.

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Sayak

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