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2.58: Similar to electron diffraction, a neutron diffraction microscope is also used for the determination of the structure of molecules. If the wavelength used here is 800 pm, calculate the characteristic velocity associated with the neutron.

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Given the wavelength of neutron: \lambda = 800\ pm

and the mass of neutron m =1.675\times10^{-27}kg

So, according to de -Broglie's equation,

\lambda = \frac{h}{mv}

Substituting the values in above equation:

800\times10^{-12} m = \frac{6.626\times10^{-34}Js}{(1.675\times10^{-27}kg)\times(v)}

\Rightarrow v = \frac{6.626\times10^{-34}Js}{(1.675\times10^{-27}kg)\times(800\times10^{-12}m)}

v= 4.94\times10^4 m/s

Posted by

Divya Prakash Singh

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