Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Solve 3x + 8 > 2, when x is a real number

Q4.    Solve 3x + 8 >2, when

                (ii) x is a real number.

Answers (1)

best_answer

Given :   3x + 8 >2

\Rightarrow      3x + 8 >2

\Rightarrow \, \, \, 3x> -6

Divide by 3 from both side 

\Rightarrow \, \, \, \frac{3}{3}x> \frac{-6}{3}

 \Rightarrow \, \, \, x> - 2

 

x are  real numbers  greater  than -2

Hence , values of x can be as  x\in (-2,\infty )

Posted by

seema garhwal

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Supplementary Result 2025 LIVE: CBSE 12 compartment results out, Class 10 supply result soon; updates
anam-khan

CBSE 12 supplementary result 2025 out at results.cbse.nic.in; 38.36% pass
anam-khan

CBSE Supplementary Result 2025 LIVE: Class 10, 12 supplementary result soon on results.cbse.nic.in

Latest Question