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Solve the inequality for real  x.

    Q7.    3(x-1) \leq 2(x-3)

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Given :   3(x-1) \leq 2(x-3)

\Rightarrow      3(x-1) \leq 2(x-3)

\Rightarrow \, \, \, 3x-3\leq 2x-6

\Rightarrow \, \, \, 3x-2x\leq -6+3

\Rightarrow \, \, \, x\leq -3

x are  real numbers less than equal to  -3

Hence , values of x can be as ,  x\in (-\infty ,-3]

Posted by

seema garhwal

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