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  • Solve the inequality for real x 37 - (3x + 5) greater than or equal to 9 x - 8( x - 3)

Solve the inequality for real x

    Q14.    37 - (3x + 5) \geq 9x - 8(x-3)

Answers (1)

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Given :   37 - (3x + 5) \geq 9x - 8(x-3)

\Rightarrow      37 - (3x + 5) \geq 9x - 8(x-3)

\Rightarrow \, \, \, 37 - 3x - 5 \geq 9x - 8x+24

\Rightarrow \, \, \, 32 - 3x \geq x+24

 \Rightarrow \, \, \, 32 - 24 \geq x+3x

\Rightarrow \, \, \, 8 \geq 4x

\Rightarrow \, \, \, 2\geq x

x are  real numbers less than equal to 2.

Hence , values of x can be  as  x\in (-\infty ,2]

Posted by

seema garhwal

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