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7.50     The degree of ionization of a 0.1M bromoacetic acid solution is 0.132. Calculate the pH of the solution and the pKa of bromoacetic acid.

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We have,

Degree of ionization(a) = 0.132 
Concentration of bromoacetic acid (C) =  0.1 M

Thus the concentration of   H_{3}O^+ = C.a
                                                           = 0.0132 

Therefore 
p^H = -\log[H^+] = -\log(0.0132)
                                    = 1.879 

Now, we know that, 
K_a = C.a^2
So, pK_a = -\log(C.a^2)
                  \\=-\log (0.1\times (0.0132)^2)\\ =-\log (0.0017)\\ =2.76(approx)   

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manish

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