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1.21    The following data are obtained when dinitrogen and dioxygen react together to form different compounds:
                        Mass of dinitrogen                 Mass of dioxygen
                            (i) 14 g                                           16 g
                            (ii) 14 g                                           32 g
                            (iii) 28 g                                           32 g
                            (iv) 28 g                                            80 g

        (b) Fill in the blanks in the following conversions:
                    (i) 1 km = ...................... mm = ...................... pm
                    (ii) 1 mg = ...................... kg = ...................... ng
                    (iii) 1 mL = ...................... L = ...................... dm³

Answers (1)

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(i) As we know in $1km = 1000m$ or $1m = 1000mm$ . or $1 km = 1000\times1000 mm =10^6 mm$

And $1pm = 1\times10^{-12}m$ or $1km = 10^{15} pm$

Therefore we have,

$1 km = 10^6 mm =10^{15} pm$

(ii) As we know in $1kg = 1000g$ or $1g = 1000mg$ . or $1 kg = 1000\times1000 mg$ or $1mg = \frac{1}{10^6} kg=10^{-6}kg$

And $1 ng = 10^{-9}g$ or $1ng = 10^{-9}\times1000mg$ or $1ng = 10^{-6}mg$

or $1 mg =10^6ng$ .

Therefore we have,

$1 mg = 10^{-6} kg =10^{6} ng$ .

(iii) As we know in $1L= 1000mL$ or $1mL =\frac{1}{1000}L = 10^{-3}L$

or $1dm = 0.1 m \Rightarrow 1dm = 10cm$ or $1cm = 0.1dm$

And $1mL = 1cm^3$ or we can write it as: $1mL = \frac{1dm}{10cm}\times\frac{1dm}{10cm}\times\frac{1dm}{10cm}$

And $1mL = 10^{-3}dm^3$

Therefore we have,

$1mL = 10^{-3}L =10^{-3}dm^3$

Posted by

Divya Prakash Singh

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