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Q4(4)    The function ‘t’ which maps temperature in degree Celsius into temperature in
       degree Fahrenheit is defined by t ( C ) = \frac{9 C }{5} + 32
      The value of C, when t(C) = 212.

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Given function is 
t ( C ) = \frac{9 C }{5} + 32
Now,
212 = \frac{9 (C) }{5} + 32
212 \times 5= {9 (C) } + 160
{9 (C) } =1060-160
C = \frac{900}{9} = 100
Therefore,
When t(C) = 212 , value of C is  100 

Posted by

Gautam harsolia

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