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  • The ionization constant of HF, HCOOH and HCN at 298K are 6.8 × 10^–4, 1.8 × 10^–4 and 4.8 × 10^–9 respectively. Calculate the ionization constants of the

7.43     The ionization constant of HF, HCOOH and HCN at 298K are 6.8 × 10-4, 1.8 × 10-4 and 4.8 × 10-9 respectively. Calculate the ionization constants of the corresponding conjugate base.

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best_answer

We have,
IOnization constant of hydrogen fluoride, methanoic acid and hydrogen cyanide are 6.8\times 10^{-4},\ 1.8 \times 10^{-4} and 4.8\times 10^{-9} respectively.

It is known that,
K_b = \frac{K_w}{K_a}...........................(i)

K_b of the conjugate base F^- 
=\frac{10^{-14}}{6.8 \times 10^{-4}}

=1.5 \times 10^{-11}
 

Similarly, 
By using the equation (i)
K_b of the conjugate base HCOO^- 
=\frac{10^{-14}}{1.8\times 10^{-4}}

=5.6\times 10^{-11}

Again, with the help of eq (i)
K_b of the conjugate base CN^-
=\frac{10^{-14}}{4.8\times 10^{-9}}
=2.8\times 10^{-6}

Posted by

manish

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