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The order of reactivity of following alcohols with halogen acids is

(A) CH_{3}CH_{2}-CH_{2}-OH

(B) 

(C) 

(i) (A) > (B) > (C)

(ii) (C) > (B) > (A)

(iii) (B) > (A) > (C)

(iv) (A) > (C) > (B)

Answers (1)

The alcohol reacts with the halogen acids in an order of 3^{\circ}> 2^{\circ} > 1^{\circ}.

Hence correct option is (ii) (C) > (B) > (A)

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infoexpert21

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